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Source Code
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// Made by Zainal.
// Gallery for all the simple C++ projects I did this year.
#include <iostream>
using namespace std;
void
evenNumber ()
{
int nomor = 1000;
cout << "\n Nomor genap dari 1-1000 adalah \n";
for (int i = 1; i <= nomor; i++)
{
if (i % 2 == 0) // == 0 means that if i is completely divisible by 2 to execute the print command next, if not then execute the loop again
cout << i << " ";
}
cin.get ();
}
void
luasSegitiga ()
{
int alas, tinggi;
float luas; // Float because the answer could be a decimal number
cout << "\n Mencari luas segitiga \n";
cout << "Tuliskan nilai alasnya:";
cin >> alas;
cout << "Tuliskan nilai tingginya:";
cin >> tinggi;
luas = (0.5) * alas * tinggi;
cout << "\n Jadi luasnya adalah: " << luas;
cin.get ();
}
void
oddNumber ()
{
cout << "\n Odd Numbers from 1-1000 \n";
int nomor = 1000;
for (int i = 1; i <= nomor; i++)
{
if (i % 2)
{
cout << i << " ";
}
}
cin.get ();
}
void
primeNumber ()
{
cout << "\n Prime Numbers from 1-1000 \n";
int i, j, count = 0;
for (i = 1; i <= 1000; i++)
{
for (j = 2; j < i; j++)
{
if (i % j == 0)
{
count++;
break;
cout << count++ << "\n ";
}
}
if (count == 0 && i != 1)
cout << i << "\t ";
count = 0;
}
cin.get ();
}
void
leapYear ()
{
cout << "\n Tahun kabisat dari 1900-2050 \n";
for (int i = 1900; i <= 2050; i++)
{
if ((i % 400 == 0) || (i % 4 == 0 && i % 100 != 0))
{
cout << i << " ";
}
}
cin.get ();
}
int
main ()
{
int x;
cout << "1. Even number from 1-100 \n";
cout << "2. Luas Segitiga \n";
cout << "3. Odd numbers 1-1000 \n";
cout << "4. Prime Numbers 1-100 \n";
cout << "5. Leap Years 1900-2050 1-100 \n";
cout << "Type the number for the intended program : \n \n";
cin >> x;
switch (x)
{
case 1:
evenNumber ();
break;
case 2:
luasSegitiga ();
break;
case 3:
oddNumber ();
break;
case 4:
primeNumber ();
break;
case 5:
leapYear ();
break;
default:
cout << "\n ERROR: Program not found \n";
break;
cin.get ();
return 0;
}
}
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