online compiler and debugger for c/c++

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/****************************************************************************** Online C Compiler. Code, Compile, Run and Debug C program online. Write your code in this editor and press "Run" button to compile and execute it. *******************************************************************************/ /* OF LOOPS, PARENTHESES AND CONDITIONS! /* A conversation with computer to display artistic features on screen. */ #include <stdio.h> /* Hey computer! Remember the things that you already are familiar with? */ main() /* Let me get straight to the point here! */ { /* 1) Can you start by defining two variables which are integers? Name them i and j! */ int i, j; /* I would like you to first ask me to enter a number of my choice! */ printf ("Enter a number of your choice:"); /* you will know when i entered the number */ scanf ("%d", &i); /* please check which number i entered. If my number is less than 55, note that */ if (i < 55) /* So, like we decided earlier, if number is less than 55, let us do the following */ { /* change the value of i to 1 and check if the original number i entered was less than/equal to 111 */ for (i = 1; i<=111; i++) /* if yes, do the following */ { /* make the second integer j equal to 1. Also, please make sure j stays less than/equal to the value of 1 */ for (j = 1; j <= i; j++) /* ok! cool! if j is less than/equal to i, print "*" on the screen */ { /* print only as many times as the value of j. So, 1 time on the first try, two time on second etc!! */ printf("*",j); } /* after printing line of *s each time, go to a new line so that it looks artistic */ printf("\n"); } /* Alright! So we know what to do if i enter a number less than 55! */ return 0; /* But, what about if the number is greater than 55?! Confused face?! */ } /* Well! Let us try this for a number entered greater than 55 */ else { /* just like before, please check if the number i entered is less than or equal to 111 */ while (i <= 111) { /* if that is true, make the second integer equal to 1 */ j = 1; /* Now, as long as j is less than or equal to the number i entered, all is good */ while (j <= i) { /* we will do two new things here: */ printf("&"); /* 1) if the previous conditions satisfy, please print & for me on the screen! */ /* 2) print & as many times as the number i entered and then increase till you reach 111 */ /* for example, if i entered 8, print & eight times is a line, then nine times in a line, up to 111 */ j++; } printf("\n"); i++; } } /* we did it!!! Thank you computer! You can relax now! */ return 0; }

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Standard Input: Interactive Console Text

                

                

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